Base | Representation |
---|---|
bin | 110000000010110100101011… |
… | …111001000010100101100011 |
3 | 1000201011002212012101201002220 |
4 | 300002310223321002211203 |
5 | 210143420344030400103 |
6 | 2025221554042242123 |
7 | 62335636662215403 |
oct | 6002645371024543 |
9 | 1021132765351086 |
10 | 211300242434403 |
11 | 61365a252a5071 |
12 | 1b84749b7b6343 |
13 | 90b96b1805735 |
14 | 3a26db45a8803 |
15 | 196660e344c53 |
hex | c02d2be42963 |
211300242434403 has 4 divisors (see below), whose sum is σ = 281733656579208. Its totient is φ = 140866828289600.
The previous prime is 211300242434327. The next prime is 211300242434423. The reversal of 211300242434403 is 304434242003112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211300242434403 - 213 = 211300242426211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (211300242434423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35216707072398 + ... + 35216707072403.
It is an arithmetic number, because the mean of its divisors is an integer number (70433414144802).
Almost surely, 2211300242434403 is an apocalyptic number.
211300242434403 is a deficient number, since it is larger than the sum of its proper divisors (70433414144805).
211300242434403 is an equidigital number, since it uses as much as digits as its factorization.
211300242434403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70433414144804.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 211300242434403 its reverse (304434242003112), we get a palindrome (515734484437515).
The spelling of 211300242434403 in words is "two hundred eleven trillion, three hundred billion, two hundred forty-two million, four hundred thirty-four thousand, four hundred three".
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