2113004001331 has 8 divisors (see below), whose sum is σ = 2113632984320. Its totient is φ = 2112375125952.

The previous prime is 2113004001299. The next prime is 2113004001337. The reversal of 2113004001331 is 1331004003112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2113004001331 - 2⁵ = 2113004001299 is a prime.

It is a super-2 number, since 2×2113004001331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2113004001299 and 2113004001308.

It is not an unprimeable number, because it can be changed into a prime (2113004001337) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54017326 + ... + 54056428.

It is an arithmetic number, because the mean of its divisors is an integer number (264204123040).

Almost surely, 2^{2113004001331} is an apocalyptic number.

2113004001331 is a deficient number, since it is larger than the sum of its proper divisors (628982989).

2113004001331 is an equidigital number, since it uses as much as digits as its factorization.

2113004001331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53805.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2113004001331 its reverse (1331004003112), we get a palindrome (3444008004443).

The spelling of 2113004001331 in words is "two trillion, one hundred thirteen billion, four million, one thousand, three hundred thirty-one".