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21130042400003 = 191112107494737
BaseRepresentation
bin1001100110111101110001…
…01010111101110100000011
32202211000022222121022122002
410303132320222331310003
510232143311323300003
6112535001340334215
74310411101650305
oct463367052756403
982730288538562
1021130042400003
116807223091889
12245318854436b
13ba372917b154
145309b1649975
15269993038a88
hex1337b8abdd03

21130042400003 has 4 divisors (see below), whose sum is σ = 22242149894760. Its totient is φ = 20017934905248.

The previous prime is 21130042399943. The next prime is 21130042400009. The reversal of 21130042400003 is 30000424003112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21130042400003 - 28 = 21130042399747 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21130042400009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 556053747350 + ... + 556053747387.

It is an arithmetic number, because the mean of its divisors is an integer number (5560537473690).

Almost surely, 221130042400003 is an apocalyptic number.

21130042400003 is a deficient number, since it is larger than the sum of its proper divisors (1112107494757).

21130042400003 is a wasteful number, since it uses less digits than its factorization.

21130042400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1112107494756.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 21130042400003 its reverse (30000424003112), we get a palindrome (51130466403115).

The spelling of 21130042400003 in words is "twenty-one trillion, one hundred thirty billion, forty-two million, four hundred thousand, three".

Divisors: 1 19 1112107494737 21130042400003