Base | Representation |
---|---|
bin | 10011101011011100… |
… | …101101111111000001 |
3 | 2000112120220102021101 |
4 | 103223130231333001 |
5 | 321233242341304 |
6 | 13412414054401 |
7 | 1345423255603 |
oct | 235334557701 |
9 | 60476812241 |
10 | 21130043329 |
11 | 8a633a432a |
12 | 41184aa401 |
13 | 1cb9847225 |
14 | 1046405173 |
15 | 83a0888a4 |
hex | 4eb72dfc1 |
21130043329 has 2 divisors, whose sum is σ = 21130043330. Its totient is φ = 21130043328.
The previous prime is 21130043303. The next prime is 21130043353. The reversal of 21130043329 is 92334003112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15952953025 + 5177090304 = 126305^2 + 71952^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21130043329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21130043297 and 21130043306.
It is not a weakly prime, because it can be changed into another prime (21130043929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565021664 + 10565021665.
It is an arithmetic number, because the mean of its divisors is an integer number (10565021665).
Almost surely, 221130043329 is an apocalyptic number.
It is an amenable number.
21130043329 is a deficient number, since it is larger than the sum of its proper divisors (1).
21130043329 is an equidigital number, since it uses as much as digits as its factorization.
21130043329 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 28.
The spelling of 21130043329 in words is "twenty-one billion, one hundred thirty million, forty-three thousand, three hundred twenty-nine".
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