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211310313121307 is a prime number
BaseRepresentation
bin110000000010111110000100…
…001001101010011000011011
31000201012001212001011121102202
4300002332010021222120123
5210144102010124340212
62025230341232120415
762336444355514541
oct6002760411523033
91021161761147382
10211310313121307
116136a2229aa204
121b84943039610b
1390ba62804227a
143a2768bc8bd91
1519669ed5170c2
hexc02f8426a61b

211310313121307 has 2 divisors, whose sum is σ = 211310313121308. Its totient is φ = 211310313121306.

The previous prime is 211310313121273. The next prime is 211310313121331. The reversal of 211310313121307 is 703121313013112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211310313121307 - 228 = 211310044685851 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211310313121307.

It is not a weakly prime, because it can be changed into another prime (211310313121357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655156560653 + 105655156560654.

It is an arithmetic number, because the mean of its divisors is an integer number (105655156560654).

Almost surely, 2211310313121307 is an apocalyptic number.

211310313121307 is a deficient number, since it is larger than the sum of its proper divisors (1).

211310313121307 is an equidigital number, since it uses as much as digits as its factorization.

211310313121307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268, while the sum is 29.

Adding to 211310313121307 its reverse (703121313013112), we get a palindrome (914431626134419).

The spelling of 211310313121307 in words is "two hundred eleven trillion, three hundred ten billion, three hundred thirteen million, one hundred twenty-one thousand, three hundred seven".