Base | Representation |
---|---|
bin | 110000000010111110000100… |
… | …001001101010011000011011 |
3 | 1000201012001212001011121102202 |
4 | 300002332010021222120123 |
5 | 210144102010124340212 |
6 | 2025230341232120415 |
7 | 62336444355514541 |
oct | 6002760411523033 |
9 | 1021161761147382 |
10 | 211310313121307 |
11 | 6136a2229aa204 |
12 | 1b84943039610b |
13 | 90ba62804227a |
14 | 3a2768bc8bd91 |
15 | 19669ed5170c2 |
hex | c02f8426a61b |
211310313121307 has 2 divisors, whose sum is σ = 211310313121308. Its totient is φ = 211310313121306.
The previous prime is 211310313121273. The next prime is 211310313121331. The reversal of 211310313121307 is 703121313013112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211310313121307 - 228 = 211310044685851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211310313121307.
It is not a weakly prime, because it can be changed into another prime (211310313121357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655156560653 + 105655156560654.
It is an arithmetic number, because the mean of its divisors is an integer number (105655156560654).
Almost surely, 2211310313121307 is an apocalyptic number.
211310313121307 is a deficient number, since it is larger than the sum of its proper divisors (1).
211310313121307 is an equidigital number, since it uses as much as digits as its factorization.
211310313121307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 29.
Adding to 211310313121307 its reverse (703121313013112), we get a palindrome (914431626134419).
The spelling of 211310313121307 in words is "two hundred eleven trillion, three hundred ten billion, three hundred thirteen million, one hundred twenty-one thousand, three hundred seven".
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