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2113112202001 = 2179996936199
BaseRepresentation
bin11110101111111111010…
…011010101101100010001
321111000022102102001212221
4132233333103111230101
5234110123210431001
64254430024021041
7305444614233523
oct36577723255421
97430272361787
102113112202001
11745190827369
122a1651001781
1312435b76c208
14743bd125a13
1539e7842e1a1
hex1ebff4d5b11

2113112202001 has 4 divisors (see below), whose sum is σ = 2113209160000. Its totient is φ = 2113015244004.

The previous prime is 2113112201999. The next prime is 2113112202007. The reversal of 2113112202001 is 1002022113112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2113112202001 - 21 = 2113112201999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113112202007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48446301 + ... + 48489898.

It is an arithmetic number, because the mean of its divisors is an integer number (528302290000).

Almost surely, 22113112202001 is an apocalyptic number.

It is an amenable number.

2113112202001 is a deficient number, since it is larger than the sum of its proper divisors (96957999).

2113112202001 is an equidigital number, since it uses as much as digits as its factorization.

2113112202001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96957998.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2113112202001 its reverse (1002022113112), we get a palindrome (3115134315113).

The spelling of 2113112202001 in words is "two trillion, one hundred thirteen billion, one hundred twelve million, two hundred two thousand, one".

Divisors: 1 21799 96936199 2113112202001