Base | Representation |
---|---|
bin | 1001100110111111110011… |
… | …00100000010100001100011 |
3 | 2202211010010212012011211120 |
4 | 10303133321210002201203 |
5 | 10232203024030301311 |
6 | 112535301351143323 |
7 | 4310450061533424 |
oct | 463377144024143 |
9 | 82733125164746 |
10 | 21131131103331 |
11 | 68077316907a7 |
12 | 2453431074b43 |
13 | ba38708a4cc2 |
14 | 530a7608764b |
15 | 269a088dc706 |
hex | 1337f9902863 |
21131131103331 has 4 divisors (see below), whose sum is σ = 28174841471112. Its totient is φ = 14087420735552.
The previous prime is 21131131103323. The next prime is 21131131103359. The reversal of 21131131103331 is 13330113113112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21131131103331 - 23 = 21131131103323 is a prime.
It is a super-2 number, since 2×211311311033312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (21131131103531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3521855183886 + ... + 3521855183891.
It is an arithmetic number, because the mean of its divisors is an integer number (7043710367778).
Almost surely, 221131131103331 is an apocalyptic number.
21131131103331 is a deficient number, since it is larger than the sum of its proper divisors (7043710367781).
21131131103331 is an equidigital number, since it uses as much as digits as its factorization.
21131131103331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7043710367780.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 21131131103331 its reverse (13330113113112), we get a palindrome (34461244216443).
The spelling of 21131131103331 in words is "twenty-one trillion, one hundred thirty-one billion, one hundred thirty-one million, one hundred three thousand, three hundred thirty-one".
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