Base | Representation |
---|---|
bin | 1001100110111111110011… |
… | …10000010111010111000011 |
3 | 2202211010011002021100000220 |
4 | 10303133321300113113003 |
5 | 10232203030342200103 |
6 | 112535301544314123 |
7 | 4310450131151442 |
oct | 463377160272703 |
9 | 82733132240026 |
10 | 21131134334403 |
11 | 6807733498305 |
12 | 2453432172943 |
13 | ba3871466892 |
14 | 530a76688d59 |
15 | 269a08d29c53 |
hex | 1337f9c175c3 |
21131134334403 has 16 divisors (see below), whose sum is σ = 29399985628416. Its totient is φ = 13474859071520.
The previous prime is 21131134334389. The next prime is 21131134334413. The reversal of 21131134334403 is 30443343113112.
It is a cyclic number.
It is not a de Polignac number, because 21131134334403 - 25 = 21131134334371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (21131134334413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15748576 + ... + 17037602.
It is an arithmetic number, because the mean of its divisors is an integer number (1837499101776).
Almost surely, 221131134334403 is an apocalyptic number.
21131134334403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
21131134334403 is a deficient number, since it is larger than the sum of its proper divisors (8268851294013).
21131134334403 is a wasteful number, since it uses less digits than its factorization.
21131134334403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1526634.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 21131134334403 its reverse (30443343113112), we get a palindrome (51574477447515).
The spelling of 21131134334403 in words is "twenty-one trillion, one hundred thirty-one billion, one hundred thirty-four million, three hundred thirty-four thousand, four hundred three".
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