211311443314131 has 8 divisors (see below), whose sum is σ = 283012037683200. Its totient is φ = 140242572243912.

The previous prime is 211311443314121. The next prime is 211311443314163. The reversal of 211311443314131 is 131413344113112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 211311443314131 - 2⁷ = 211311443314003 is a prime.

It is a super-2 number, since 2×211311443314131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211311443314092 and 211311443314101.

It is not an unprimeable number, because it can be changed into a prime (211311443314121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 157930823931 + ... + 157930825268.

It is an arithmetic number, because the mean of its divisors is an integer number (35376504710400).

Almost surely, 2^{211311443314131} is an apocalyptic number.

211311443314131 is a deficient number, since it is larger than the sum of its proper divisors (71700594369069).

211311443314131 is a wasteful number, since it uses less digits than its factorization.

211311443314131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 315861649425.

The product of its digits is 10368, while the sum is 33.

Adding to 211311443314131 its reverse (131413344113112), we get a palindrome (342724787427243).

The spelling of 211311443314131 in words is "two hundred eleven trillion, three hundred eleven billion, four hundred forty-three million, three hundred fourteen thousand, one hundred thirty-one".