21131200011331 has 4 divisors (see below), whose sum is σ = 22243368433000. Its totient is φ = 20019031589664.

The previous prime is 21131200011329. The next prime is 21131200011349. The reversal of 21131200011331 is 13311000213112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21131200011331 - 2¹ = 21131200011329 is a prime.

It is a super-3 number, since 3×21131200011331³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 1112168421649 = 21131200011331 / (2 + 1 + 1 + 3 + 1 + 2 + 0 + 0 + 0 + 1 + 1 + 3 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21131200011299 and 21131200011308.

It is not an unprimeable number, because it can be changed into a prime (21131200011301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 556084210806 + ... + 556084210843.

It is an arithmetic number, because the mean of its divisors is an integer number (5560842108250).

Almost surely, 2^{21131200011331} is an apocalyptic number.

21131200011331 is a deficient number, since it is larger than the sum of its proper divisors (1112168421669).

21131200011331 is a wasteful number, since it uses less digits than its factorization.

21131200011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1112168421668.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 21131200011331 its reverse (13311000213112), we get a palindrome (34442200224443).

The spelling of 21131200011331 in words is "twenty-one trillion, one hundred thirty-one billion, two hundred million, eleven thousand, three hundred thirty-one".