Base | Representation |
---|---|
bin | 1100010011001100101… |
… | …1011000111000101001 |
3 | 202012102200211220010101 |
4 | 3010303023120320221 |
5 | 11430231334133113 |
6 | 241024141545401 |
7 | 21160336354111 |
oct | 3046313307051 |
9 | 665380756111 |
10 | 211312021033 |
11 | 81687144013 |
12 | 34b53b75261 |
13 | 16c07a93049 |
14 | a3285b4041 |
15 | 576b5e92dd |
hex | 31332d8e29 |
211312021033 has 2 divisors, whose sum is σ = 211312021034. Its totient is φ = 211312021032.
The previous prime is 211312021027. The next prime is 211312021069. The reversal of 211312021033 is 330120213112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 175601226304 + 35710794729 = 419048^2 + 188973^2 .
It is a cyclic number.
It is not a de Polignac number, because 211312021033 - 25 = 211312021001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211312021033.
It is not a weakly prime, because it can be changed into another prime (211312021003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105656010516 + 105656010517.
It is an arithmetic number, because the mean of its divisors is an integer number (105656010517).
Almost surely, 2211312021033 is an apocalyptic number.
It is an amenable number.
211312021033 is a deficient number, since it is larger than the sum of its proper divisors (1).
211312021033 is an equidigital number, since it uses as much as digits as its factorization.
211312021033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 211312021033 its reverse (330120213112), we get a palindrome (541432234145).
The spelling of 211312021033 in words is "two hundred eleven billion, three hundred twelve million, twenty-one thousand, thirty-three".
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