Base | Representation |
---|---|
bin | 11110101111111111110… |
… | …110000101101001011011 |
3 | 21111000100001112212112020 |
4 | 132233333312011221123 |
5 | 234110133023430243 |
6 | 4254430551145523 |
7 | 305445054533361 |
oct | 36577766055133 |
9 | 7430301485466 |
10 | 2113121311323 |
11 | 745195989330 |
12 | 2a16540752a3 |
13 | 12436060b549 |
14 | 743c0417631 |
15 | 39e7912d283 |
hex | 1ebffd85a5b |
2113121311323 has 16 divisors (see below), whose sum is σ = 3097093836672. Its totient is φ = 1270903400000.
The previous prime is 2113121311309. The next prime is 2113121311381. The reversal of 2113121311323 is 3231131213112.
It is a cyclic number.
It is not a de Polignac number, because 2113121311323 - 222 = 2113117117019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2113121311293 and 2113121311302.
It is not an unprimeable number, because it can be changed into a prime (2113121311303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244400178 + ... + 244408823.
It is an arithmetic number, because the mean of its divisors is an integer number (193568364792).
Almost surely, 22113121311323 is an apocalyptic number.
2113121311323 is a deficient number, since it is larger than the sum of its proper divisors (983972525349).
2113121311323 is a wasteful number, since it uses less digits than its factorization.
2113121311323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 488809146.
The product of its digits is 648, while the sum is 24.
Adding to 2113121311323 its reverse (3231131213112), we get a palindrome (5344252524435).
The spelling of 2113121311323 in words is "two trillion, one hundred thirteen billion, one hundred twenty-one million, three hundred eleven thousand, three hundred twenty-three".
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