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211321130323 is a prime number
BaseRepresentation
bin1100010011001110111…
…0001000110101010011
3202012110022222200201111
43010303232020311103
511430241202132243
6241025105114151
721160506653602
oct3046356106523
9665408880644
10211321130323
11816912a5a56
1234b57028957
1316c09932364
14a3298a5a39
15576c2e839d
hex3133b88d53

211321130323 has 2 divisors, whose sum is σ = 211321130324. Its totient is φ = 211321130322.

The previous prime is 211321130299. The next prime is 211321130357. The reversal of 211321130323 is 323031123112.

211321130323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211321130323 - 217 = 211320999251 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211321130294 and 211321130303.

It is not a weakly prime, because it can be changed into another prime (211321131323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105660565161 + 105660565162.

It is an arithmetic number, because the mean of its divisors is an integer number (105660565162).

Almost surely, 2211321130323 is an apocalyptic number.

211321130323 is a deficient number, since it is larger than the sum of its proper divisors (1).

211321130323 is an equidigital number, since it uses as much as digits as its factorization.

211321130323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 211321130323 its reverse (323031123112), we get a palindrome (534352253435).

The spelling of 211321130323 in words is "two hundred eleven billion, three hundred twenty-one million, one hundred thirty thousand, three hundred twenty-three".