Base | Representation |
---|---|
bin | 111110111110101… |
… | …0000110001100011 |
3 | 12110021101021012021 |
4 | 1331331100301203 |
5 | 13311440231431 |
6 | 545405242311 |
7 | 103240000306 |
oct | 17575206143 |
9 | 5407337167 |
10 | 2113211491 |
11 | 994942086 |
12 | 4ab863397 |
13 | 278a65401 |
14 | 160928b3d |
15 | c57c6b11 |
hex | 7df50c63 |
2113211491 has 2 divisors, whose sum is σ = 2113211492. Its totient is φ = 2113211490.
The previous prime is 2113211473. The next prime is 2113211539. The reversal of 2113211491 is 1941123112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113211491 - 25 = 2113211459 is a prime.
It is not a weakly prime, because it can be changed into another prime (2113211431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056605745 + 1056605746.
It is an arithmetic number, because the mean of its divisors is an integer number (1056605746).
Almost surely, 22113211491 is an apocalyptic number.
2113211491 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113211491 is an equidigital number, since it uses as much as digits as its factorization.
2113211491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 432, while the sum is 25.
The square root of 2113211491 is about 45969.6801272317. The cubic root of 2113211491 is about 1283.2590070107.
It can be divided in two parts, 21132 and 11491, that added together give a palindrome (32623).
The spelling of 2113211491 in words is "two billion, one hundred thirteen million, two hundred eleven thousand, four hundred ninety-one".
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