2113214123131 has 2 divisors, whose sum is σ = 2113214123132. Its totient is φ = 2113214123130.

The previous prime is 2113214123099. The next prime is 2113214123143. The reversal of 2113214123131 is 1313214123112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2113214123131 - 2⁵ = 2113214123099 is a prime.

It is a super-2 number, since 2×2113214123131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113214123096 and 2113214123105.

It is not a weakly prime, because it can be changed into another prime (2113214123161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056607061565 + 1056607061566.

It is an arithmetic number, because the mean of its divisors is an integer number (1056607061566).

Almost surely, 2^{2113214123131} is an apocalyptic number.

2113214123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113214123131 is an equidigital number, since it uses as much as digits as its factorization.

2113214123131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 864, while the sum is 25.

Adding to 2113214123131 its reverse (1313214123112), we get a palindrome (3426428246243).

The spelling of 2113214123131 in words is "two trillion, one hundred thirteen billion, two hundred fourteen million, one hundred twenty-three thousand, one hundred thirty-one".