Base | Representation |
---|---|
bin | 11110110000000101110… |
… | …111111000000110001011 |
3 | 21111000121002211220122211 |
4 | 132300011313320012023 |
5 | 234110334421142103 |
6 | 4254445002525551 |
7 | 305450423252161 |
oct | 36600567700613 |
9 | 7430532756584 |
10 | 2113222443403 |
11 | 745237a83365 |
12 | 2a1681b068b7 |
13 | 12437855a406 |
14 | 743cda21231 |
15 | 39e82e5836d |
hex | 1ec05df818b |
2113222443403 has 8 divisors (see below), whose sum is σ = 2115687283776. Its totient is φ = 2110758198600.
The previous prime is 2113222443373. The next prime is 2113222443413. The reversal of 2113222443403 is 3043442223112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2113222443403 - 213 = 2113222435211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2113222443413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7160188 + ... + 7449478.
It is an arithmetic number, because the mean of its divisors is an integer number (264460910472).
Almost surely, 22113222443403 is an apocalyptic number.
2113222443403 is a deficient number, since it is larger than the sum of its proper divisors (2464840373).
2113222443403 is an equidigital number, since it uses as much as digits as its factorization.
2113222443403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 297785.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 2113222443403 its reverse (3043442223112), we get a palindrome (5156664666515).
The spelling of 2113222443403 in words is "two trillion, one hundred thirteen billion, two hundred twenty-two million, four hundred forty-three thousand, four hundred three".
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