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2113222443403 = 9717523289291
BaseRepresentation
bin11110110000000101110…
…111111000000110001011
321111000121002211220122211
4132300011313320012023
5234110334421142103
64254445002525551
7305450423252161
oct36600567700613
97430532756584
102113222443403
11745237a83365
122a1681b068b7
1312437855a406
14743cda21231
1539e82e5836d
hex1ec05df818b

2113222443403 has 8 divisors (see below), whose sum is σ = 2115687283776. Its totient is φ = 2110758198600.

The previous prime is 2113222443373. The next prime is 2113222443413. The reversal of 2113222443403 is 3043442223112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2113222443403 - 213 = 2113222435211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113222443413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7160188 + ... + 7449478.

It is an arithmetic number, because the mean of its divisors is an integer number (264460910472).

Almost surely, 22113222443403 is an apocalyptic number.

2113222443403 is a deficient number, since it is larger than the sum of its proper divisors (2464840373).

2113222443403 is an equidigital number, since it uses as much as digits as its factorization.

2113222443403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 297785.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 2113222443403 its reverse (3043442223112), we get a palindrome (5156664666515).

The spelling of 2113222443403 in words is "two trillion, one hundred thirteen billion, two hundred twenty-two million, four hundred forty-three thousand, four hundred three".

Divisors: 1 971 7523 289291 7304833 280901561 2176336193 2113222443403