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211323112313083 is a prime number
BaseRepresentation
bin110000000011001001111111…
…000010101101000011111011
31000201020021220001002220210121
4300003021333002231003323
5210144304213223004313
62025240255251154111
762340406503040501
oct6003117702550373
91021207801086717
10211323112313083
11613746a079a451
121b84ba028a5937
1390bb8b7935b24
143a28143aa4671
151966eec00028d
hexc0327f0ad0fb

211323112313083 has 2 divisors, whose sum is σ = 211323112313084. Its totient is φ = 211323112313082.

The previous prime is 211323112313011. The next prime is 211323112313119. The reversal of 211323112313083 is 380313211323112.

211323112313083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211323112313083 - 213 = 211323112304891 is a prime.

It is a super-2 number, since 2×2113231123130832 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211323112310083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105661556156541 + 105661556156542.

It is an arithmetic number, because the mean of its divisors is an integer number (105661556156542).

Almost surely, 2211323112313083 is an apocalyptic number.

211323112313083 is a deficient number, since it is larger than the sum of its proper divisors (1).

211323112313083 is an equidigital number, since it uses as much as digits as its factorization.

211323112313083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 34.

Adding to 211323112313083 its reverse (380313211323112), we get a palindrome (591636323636195).

The spelling of 211323112313083 in words is "two hundred eleven trillion, three hundred twenty-three billion, one hundred twelve million, three hundred thirteen thousand, eighty-three".