211324433334041 has 2 divisors, whose sum is σ = 211324433334042. Its totient is φ = 211324433334040.

The previous prime is 211324433334017. The next prime is 211324433334059. The reversal of 211324433334041 is 140433334423112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 199091507380441 + 12232925953600 = 14109979^2 + 3497560^2 .

It is a cyclic number.

It is not a de Polignac number, because 211324433334041 - 2¹⁸ = 211324433071897 is a prime.

It is a super-2 number, since 2×211324433334041² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211324433333986 and 211324433334004.

It is not a weakly prime, because it can be changed into another prime (211324433334941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105662216667020 + 105662216667021.

It is an arithmetic number, because the mean of its divisors is an integer number (105662216667021).

Almost surely, 2^{211324433334041} is an apocalyptic number.

It is an amenable number.

211324433334041 is a deficient number, since it is larger than the sum of its proper divisors (1).

211324433334041 is an equidigital number, since it uses as much as digits as its factorization.

211324433334041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 38.

Adding to 211324433334041 its reverse (140433334423112), we get a palindrome (351757767757153).

The spelling of 211324433334041 in words is "two hundred eleven trillion, three hundred twenty-four billion, four hundred thirty-three million, three hundred thirty-four thousand, forty-one".