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21133103113 = 37571164949
BaseRepresentation
bin10011101011101000…
…011001000000001001
32000112210122212111201
4103223220121000021
5321240033244423
613413003424201
71345461261343
oct235350310011
960483585451
1021133103113
118a650a4181
124119525061
131cba378b55
1410469a0293
1583a4902ad
hex4eba19009

21133103113 has 4 divisors (see below), whose sum is σ = 21704268100. Its totient is φ = 20561938128.

The previous prime is 21133103081. The next prime is 21133103119. The reversal of 21133103113 is 31130133112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18809573904 + 2323529209 = 137148^2 + 48203^2 .

It is a cyclic number.

It is not a de Polignac number, because 21133103113 - 25 = 21133103081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21133103119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285582438 + ... + 285582511.

It is an arithmetic number, because the mean of its divisors is an integer number (5426067025).

Almost surely, 221133103113 is an apocalyptic number.

It is an amenable number.

21133103113 is a deficient number, since it is larger than the sum of its proper divisors (571164987).

21133103113 is an equidigital number, since it uses as much as digits as its factorization.

21133103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 571164986.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 21133103113 its reverse (31130133112), we get a palindrome (52263236225).

The spelling of 21133103113 in words is "twenty-one billion, one hundred thirty-three million, one hundred three thousand, one hundred thirteen".

Divisors: 1 37 571164949 21133103113