2113311102433 has 2 divisors, whose sum is σ = 2113311102434. Its totient is φ = 2113311102432.

The previous prime is 2113311102421. The next prime is 2113311102439. The reversal of 2113311102433 is 3342011133112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1752004318689 + 361306783744 = 1323633^2 + 601088^2 .

It is a cyclic number.

It is not a de Polignac number, because 2113311102433 - 2²¹ = 2113309005281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2113311102398 and 2113311102407.

It is not a weakly prime, because it can be changed into another prime (2113311102439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056655551216 + 1056655551217.

It is an arithmetic number, because the mean of its divisors is an integer number (1056655551217).

Almost surely, 2^{2113311102433} is an apocalyptic number.

It is an amenable number.

2113311102433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113311102433 is an equidigital number, since it uses as much as digits as its factorization.

2113311102433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 2113311102433 its reverse (3342011133112), we get a palindrome (5455322235545).

The spelling of 2113311102433 in words is "two trillion, one hundred thirteen billion, three hundred eleven million, one hundred two thousand, four hundred thirty-three".