Base | Representation |
---|---|
bin | 11110110000001011001… |
… | …010000101100010011001 |
3 | 21111000211021200021221101 |
4 | 132300023022011202121 |
5 | 234111030120300004 |
6 | 4254501451111401 |
7 | 305452550663302 |
oct | 36601312054231 |
9 | 7430737607841 |
10 | 2113311103129 |
11 | 745283029766 |
12 | 2a16a7742561 |
13 | 124390a302a5 |
14 | 743db6dd7a9 |
15 | 39e8ab1cba4 |
hex | 1ec0b285899 |
2113311103129 has 2 divisors, whose sum is σ = 2113311103130. Its totient is φ = 2113311103128.
The previous prime is 2113311103031. The next prime is 2113311103151. The reversal of 2113311103129 is 9213011133112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2068419240000 + 44891863129 = 1438200^2 + 211877^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113311103129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2113311103097 and 2113311103106.
It is not a weakly prime, because it can be changed into another prime (2113311104129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056655551564 + 1056655551565.
It is an arithmetic number, because the mean of its divisors is an integer number (1056655551565).
Almost surely, 22113311103129 is an apocalyptic number.
It is an amenable number.
2113311103129 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113311103129 is an equidigital number, since it uses as much as digits as its factorization.
2113311103129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 2113311103129 in words is "two trillion, one hundred thirteen billion, three hundred eleven million, one hundred three thousand, one hundred twenty-nine".
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