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2113313302433 is a prime number
BaseRepresentation
bin11110110000001011010…
…010011110011110100001
321111000211102211000211002
4132300023102132132201
5234111031201134213
64254502010201345
7305452605453254
oct36601322363641
97430742730732
102113313302433
117452842a1073
122a16a8423255
13124391320358
14743dbb1309b
1539e8ae04658
hex1ec0b49e7a1

2113313302433 has 2 divisors, whose sum is σ = 2113313302434. Its totient is φ = 2113313302432.

The previous prime is 2113313302411. The next prime is 2113313302511. The reversal of 2113313302433 is 3342033133112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1286073938704 + 827239363729 = 1134052^2 + 909527^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113313302433 is a prime.

It is a super-2 number, since 2×21133133024332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113313302396 and 2113313302405.

It is not a weakly prime, because it can be changed into another prime (2113313322433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056656651216 + 1056656651217.

It is an arithmetic number, because the mean of its divisors is an integer number (1056656651217).

Almost surely, 22113313302433 is an apocalyptic number.

It is an amenable number.

2113313302433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113313302433 is an equidigital number, since it uses as much as digits as its factorization.

2113313302433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 2113313302433 its reverse (3342033133112), we get a palindrome (5455346435545).

The spelling of 2113313302433 in words is "two trillion, one hundred thirteen billion, three hundred thirteen million, three hundred two thousand, four hundred thirty-three".