Base | Representation |
---|---|
bin | 11110110000001011111… |
… | …100111101111011010101 |
3 | 21111000212012202221110202 |
4 | 132300023330331323111 |
5 | 234111042024110201 |
6 | 4254503045030245 |
7 | 305453102235143 |
oct | 36601374757325 |
9 | 7430765687422 |
10 | 2113324441301 |
11 | 74528a609947 |
12 | 2a16b00b5385 |
13 | 1243937203b8 |
14 | 743dd3b2593 |
15 | 39e8bda4c6b |
hex | 1ec0bf3ded5 |
2113324441301 has 16 divisors (see below), whose sum is σ = 2205123755520. Its totient is φ = 2023108107840.
The previous prime is 2113324441279. The next prime is 2113324441309. The reversal of 2113324441301 is 1031444233112.
It is a cyclic number.
It is not a de Polignac number, because 2113324441301 - 210 = 2113324440277 is a prime.
It is a super-2 number, since 2×21133244413012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113324441309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 308315 + ... + 2078871.
It is an arithmetic number, because the mean of its divisors is an integer number (137820234720).
Almost surely, 22113324441301 is an apocalyptic number.
It is an amenable number.
2113324441301 is a deficient number, since it is larger than the sum of its proper divisors (91799314219).
2113324441301 is a wasteful number, since it uses less digits than its factorization.
2113324441301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1771004.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 2113324441301 its reverse (1031444233112), we get a palindrome (3144768674413).
The spelling of 2113324441301 in words is "two trillion, one hundred thirteen billion, three hundred twenty-four million, four hundred forty-one thousand, three hundred one".
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