Base | Representation |
---|---|
bin | 11110110000001100010… |
… | …011110100110100000001 |
3 | 21111000212122001100220221 |
4 | 132300030103310310001 |
5 | 234111100042331111 |
6 | 4254503421303041 |
7 | 305453204202364 |
oct | 36601423646401 |
9 | 7430778040827 |
10 | 2113330433281 |
11 | 745292a317a1 |
12 | 2a16b2104a81 |
13 | 124394a3a852 |
14 | 744000d20db |
15 | 39e8c68a371 |
hex | 1ec0c4f4d01 |
2113330433281 has 2 divisors, whose sum is σ = 2113330433282. Its totient is φ = 2113330433280.
The previous prime is 2113330433239. The next prime is 2113330433327. The reversal of 2113330433281 is 1823340333112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2104193941056 + 9136492225 = 1450584^2 + 95585^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113330433281 - 215 = 2113330400513 is a prime.
It is a super-2 number, since 2×21133304332812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2113330433381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056665216640 + 1056665216641.
It is an arithmetic number, because the mean of its divisors is an integer number (1056665216641).
Almost surely, 22113330433281 is an apocalyptic number.
It is an amenable number.
2113330433281 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113330433281 is an equidigital number, since it uses as much as digits as its factorization.
2113330433281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 2113330433281 its reverse (1823340333112), we get a palindrome (3936670766393).
The spelling of 2113330433281 in words is "two trillion, one hundred thirteen billion, three hundred thirty million, four hundred thirty-three thousand, two hundred eighty-one".
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