Base | Representation |
---|---|
bin | 11110110000001100011… |
… | …111001001001101001001 |
3 | 21111000212211122010000222 |
4 | 132300030133021031021 |
5 | 234111101322303033 |
6 | 4254504005035425 |
7 | 305453241341015 |
oct | 36601437111511 |
9 | 7430784563028 |
10 | 2113333400393 |
11 | 745294678a56 |
12 | 2a16b30b5b75 |
13 | 124395539237 |
14 | 74400665545 |
15 | 39e8ca74598 |
hex | 1ec0c7c9349 |
2113333400393 has 2 divisors, whose sum is σ = 2113333400394. Its totient is φ = 2113333400392.
The previous prime is 2113333400267. The next prime is 2113333400411. The reversal of 2113333400393 is 3930043333112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1468866433024 + 644466967369 = 1211968^2 + 802787^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113333400393 - 216 = 2113333334857 is a prime.
It is a super-2 number, since 2×21133334003932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2113333400693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056666700196 + 1056666700197.
It is an arithmetic number, because the mean of its divisors is an integer number (1056666700197).
Almost surely, 22113333400393 is an apocalyptic number.
It is an amenable number.
2113333400393 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113333400393 is an equidigital number, since it uses as much as digits as its factorization.
2113333400393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 35.
The spelling of 2113333400393 in words is "two trillion, one hundred thirteen billion, three hundred thirty-three million, four hundred thousand, three hundred ninety-three".
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