Base | Representation |
---|---|
bin | 11110110000010000110… |
… | …110111101110011011011 |
3 | 21111001001221122212021122 |
4 | 132300100312331303123 |
5 | 234111224112112021 |
6 | 4254515145155455 |
7 | 305455122002660 |
oct | 36602066756333 |
9 | 7431057585248 |
10 | 2113406754011 |
11 | 74532201a683 |
12 | 2a171378bb8b |
13 | 1243a77b0347 |
14 | 7440a2bba67 |
15 | 39e94213bab |
hex | 1ec10dbdcdb |
2113406754011 has 4 divisors (see below), whose sum is σ = 2415322004592. Its totient is φ = 1811491503432.
The previous prime is 2113406753971. The next prime is 2113406754013. The reversal of 2113406754011 is 1104576043112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2113406754011 - 214 = 2113406737627 is a prime.
It is a super-2 number, since 2×21134067540112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2113406754013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150957625280 + ... + 150957625293.
It is an arithmetic number, because the mean of its divisors is an integer number (603830501148).
Almost surely, 22113406754011 is an apocalyptic number.
2113406754011 is a deficient number, since it is larger than the sum of its proper divisors (301915250581).
2113406754011 is an equidigital number, since it uses as much as digits as its factorization.
2113406754011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 301915250580.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 2113406754011 in words is "two trillion, one hundred thirteen billion, four hundred six million, seven hundred fifty-four thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •