2113411341130 has 32 divisors (see below), whose sum is σ = 3841271201664. Its totient is φ = 837114094656.

The previous prime is 2113411341101. The next prime is 2113411341133. The reversal of 2113411341130 is 311431143112.

It is a junction number, because it is equal to n+sod(n) for n = 2113411341095 and 2113411341104.

It is not an unprimeable number, because it can be changed into a prime (2113411341133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26479564 + ... + 26559256.

It is an arithmetic number, because the mean of its divisors is an integer number (120039725052).

Almost surely, 2^{2113411341130} is an apocalyptic number.

2113411341130 is a deficient number, since it is larger than the sum of its proper divisors (1727859860534).

2113411341130 is a wasteful number, since it uses less digits than its factorization.

2113411341130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105550.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 2113411341130 its reverse (311431143112), we get a palindrome (2424842484242).

The spelling of 2113411341130 in words is "two trillion, one hundred thirteen billion, four hundred eleven million, three hundred forty-one thousand, one hundred thirty".