Base | Representation |
---|---|
bin | 11110110000010001110… |
… | …010101001101110100001 |
3 | 21111001010001002210010011 |
4 | 132300101302221232201 |
5 | 234111242113303132 |
6 | 4254520504404521 |
7 | 305455402000216 |
oct | 36602162515641 |
9 | 7431101083104 |
10 | 2113422400417 |
11 | 74532a936a99 |
12 | 2a1718a76741 |
13 | 1243aaacac83 |
14 | 7440c3d1b0d |
15 | 39e957a4b47 |
hex | 1ec11ca9ba1 |
2113422400417 has 2 divisors, whose sum is σ = 2113422400418. Its totient is φ = 2113422400416.
The previous prime is 2113422400403. The next prime is 2113422400447. The reversal of 2113422400417 is 7140042243112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1544628894561 + 568793505856 = 1242831^2 + 754184^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113422400417 - 235 = 2079062662049 is a prime.
It is not a weakly prime, because it can be changed into another prime (2113422400447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056711200208 + 1056711200209.
It is an arithmetic number, because the mean of its divisors is an integer number (1056711200209).
Almost surely, 22113422400417 is an apocalyptic number.
It is an amenable number.
2113422400417 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113422400417 is an equidigital number, since it uses as much as digits as its factorization.
2113422400417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 31.
Adding to 2113422400417 its reverse (7140042243112), we get a palindrome (9253464643529).
The spelling of 2113422400417 in words is "two trillion, one hundred thirteen billion, four hundred twenty-two million, four hundred thousand, four hundred seventeen".
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