2113424123113 has 4 divisors (see below), whose sum is σ = 2113434678928. Its totient is φ = 2113413567300.

The previous prime is 2113424123101. The next prime is 2113424123117. The reversal of 2113424123113 is 3113214243112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2113424123113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113424123117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4971663 + ... + 5379988.

It is an arithmetic number, because the mean of its divisors is an integer number (528358669732).

Almost surely, 2^{2113424123113} is an apocalyptic number.

It is an amenable number.

2113424123113 is a deficient number, since it is larger than the sum of its proper divisors (10555815).

2113424123113 is a wasteful number, since it uses less digits than its factorization.

2113424123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10555814.

The product of its digits is 3456, while the sum is 28.

Adding to 2113424123113 its reverse (3113214243112), we get a palindrome (5226638366225).

The spelling of 2113424123113 in words is "two trillion, one hundred thirteen billion, four hundred twenty-four million, one hundred twenty-three thousand, one hundred thirteen".