Base | Representation |
---|---|
bin | 1100010011011100001… |
… | …0010100111011100001 |
3 | 202012121012122200121112 |
4 | 3010313002110323201 |
5 | 11430344422120101 |
6 | 241034413233105 |
7 | 21162053524121 |
oct | 3046702247341 |
9 | 665535580545 |
10 | 211376754401 |
11 | 8170a73816a |
12 | 34b71792795 |
13 | 16c18309607 |
14 | a333024c81 |
15 | 57721346bb |
hex | 3137094ee1 |
211376754401 has 8 divisors (see below), whose sum is σ = 214064647680. Its totient is φ = 208689167232.
The previous prime is 211376754367. The next prime is 211376754409. The reversal of 211376754401 is 104457673112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 211376754401 - 214 = 211376738017 is a prime.
It is a super-3 number, since 3×2113767544013 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211376754409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1524881 + ... + 1657713.
It is an arithmetic number, because the mean of its divisors is an integer number (26758080960).
Almost surely, 2211376754401 is an apocalyptic number.
It is an amenable number.
211376754401 is a deficient number, since it is larger than the sum of its proper divisors (2687893279).
211376754401 is a wasteful number, since it uses less digits than its factorization.
211376754401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153055.
The product of its (nonzero) digits is 141120, while the sum is 41.
The spelling of 211376754401 in words is "two hundred eleven billion, three hundred seventy-six million, seven hundred fifty-four thousand, four hundred one".
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