Base | Representation |
---|---|
bin | 110000000100010001110011… |
… | …110111100000110001011001 |
3 | 1000201111122221210121210021102 |
4 | 300010101303313200301121 |
5 | 210202040134431203423 |
6 | 2025335532113521145 |
7 | 62346106606440641 |
oct | 6004216367406131 |
9 | 1021448853553242 |
10 | 211400234241113 |
11 | 613a4377044455 |
12 | 1b8629468731b5 |
13 | 90c5c58706a78 |
14 | 3a2bb7c4d5521 |
15 | 19690129b1c28 |
hex | c04473de0c59 |
211400234241113 has 8 divisors (see below), whose sum is σ = 218938930041600. Its totient is φ = 203988239210560.
The previous prime is 211400234241103. The next prime is 211400234241139. The reversal of 211400234241113 is 311142432004112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 211400234241113 - 210 = 211400234240089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211400234241103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31675189088 + ... + 31675195761.
It is an arithmetic number, because the mean of its divisors is an integer number (27367366255200).
Almost surely, 2211400234241113 is an apocalyptic number.
It is an amenable number.
211400234241113 is a deficient number, since it is larger than the sum of its proper divisors (7538695800487).
211400234241113 is an equidigital number, since it uses as much as digits as its factorization.
211400234241113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63350384967.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 211400234241113 its reverse (311142432004112), we get a palindrome (522542666245225).
The spelling of 211400234241113 in words is "two hundred eleven trillion, four hundred billion, two hundred thirty-four million, two hundred forty-one thousand, one hundred thirteen".
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