Base | Representation |
---|---|
bin | 11110110000111010010… |
… | …111101100101010010010 |
3 | 21111002212111011000010102 |
4 | 132300322113230222102 |
5 | 234114140404403102 |
6 | 4255112224332402 |
7 | 305511306463634 |
oct | 36607227545222 |
9 | 7432774130112 |
10 | 2114103200402 |
11 | 74564a162106 |
12 | 2a1888a74102 |
13 | 124488b770bb |
14 | 744749aca54 |
15 | 39ed5433402 |
hex | 1ec3a5eca92 |
2114103200402 has 4 divisors (see below), whose sum is σ = 3171154800606. Its totient is φ = 1057051600200.
The previous prime is 2114103200381. The next prime is 2114103200431. The reversal of 2114103200402 is 2040023014112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2110863200161 + 3240000241 = 1452881^2 + 56921^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528525800099 + ... + 528525800102.
Almost surely, 22114103200402 is an apocalyptic number.
2114103200402 is a deficient number, since it is larger than the sum of its proper divisors (1057051600204).
2114103200402 is a wasteful number, since it uses less digits than its factorization.
2114103200402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1057051600203.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 2114103200402 its reverse (2040023014112), we get a palindrome (4154126214514).
The spelling of 2114103200402 in words is "two trillion, one hundred fourteen billion, one hundred three million, two hundred thousand, four hundred two".
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