Base | Representation |
---|---|
bin | 11110110000111010011… |
… | …100000101101010111001 |
3 | 21111002212120022111000121 |
4 | 132300322130011222321 |
5 | 234114141203221132 |
6 | 4255112305133241 |
7 | 305511322326442 |
oct | 36607234055271 |
9 | 7432776274017 |
10 | 2114104351417 |
11 | 74564a878963 |
12 | 2a188932a221 |
13 | 12448918ac86 |
14 | 74474bcc2c9 |
15 | 39ed55ae497 |
hex | 1ec3a705ab9 |
2114104351417 has 2 divisors, whose sum is σ = 2114104351418. Its totient is φ = 2114104351416.
The previous prime is 2114104351369. The next prime is 2114104351459. The reversal of 2114104351417 is 7141534014112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1387375381161 + 726728970256 = 1177869^2 + 852484^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114104351417 - 235 = 2079744613049 is a prime.
It is not a weakly prime, because it can be changed into another prime (2114104351487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057052175708 + 1057052175709.
It is an arithmetic number, because the mean of its divisors is an integer number (1057052175709).
Almost surely, 22114104351417 is an apocalyptic number.
It is an amenable number.
2114104351417 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114104351417 is an equidigital number, since it uses as much as digits as its factorization.
2114104351417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 34.
Adding to 2114104351417 its reverse (7141534014112), we get a palindrome (9255638365529).
The spelling of 2114104351417 in words is "two trillion, one hundred fourteen billion, one hundred four million, three hundred fifty-one thousand, four hundred seventeen".
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