Base | Representation |
---|---|
bin | 1100010011100100010… |
… | …1001000000010110001 |
3 | 202012200121011201000102 |
4 | 3010321011020002301 |
5 | 11430432211324411 |
6 | 241042040202145 |
7 | 21162651132302 |
oct | 3047105100261 |
9 | 665617151012 |
10 | 211411042481 |
11 | 81728027321 |
12 | 34b81169355 |
13 | 16c22453312 |
14 | a3377cc7a9 |
15 | 5775158d3b |
hex | 31391480b1 |
211411042481 has 2 divisors, whose sum is σ = 211411042482. Its totient is φ = 211411042480.
The previous prime is 211411042459. The next prime is 211411042499. The reversal of 211411042481 is 184240114112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 206669342881 + 4741699600 = 454609^2 + 68860^2 .
It is a cyclic number.
It is not a de Polignac number, because 211411042481 - 214 = 211411026097 is a prime.
It is a super-2 number, since 2×2114110424812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211411042181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105705521240 + 105705521241.
It is an arithmetic number, because the mean of its divisors is an integer number (105705521241).
Almost surely, 2211411042481 is an apocalyptic number.
It is an amenable number.
211411042481 is a deficient number, since it is larger than the sum of its proper divisors (1).
211411042481 is an equidigital number, since it uses as much as digits as its factorization.
211411042481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2048, while the sum is 29.
Adding to 211411042481 its reverse (184240114112), we get a palindrome (395651156593).
The spelling of 211411042481 in words is "two hundred eleven billion, four hundred eleven million, forty-two thousand, four hundred eighty-one".
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