211411343401 has 4 divisors (see below), whose sum is σ = 211474586752. Its totient is φ = 211348100052.

The previous prime is 211411343399. The next prime is 211411343459. The reversal of 211411343401 is 104343114112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211411343401 - 2¹ = 211411343399 is a prime.

It is a super-2 number, since 2×211411343401² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211411343201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31616661 + ... + 31623346.

It is an arithmetic number, because the mean of its divisors is an integer number (52868646688).

Almost surely, 2^211411343401 is an apocalyptic number.

It is an amenable number.

211411343401 is a deficient number, since it is larger than the sum of its proper divisors (63243351).

211411343401 is an equidigital number, since it uses as much as digits as its factorization.

211411343401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63243350.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 211411343401 its reverse (104343114112), we get a palindrome (315754457513).

The spelling of 211411343401 in words is "two hundred eleven billion, four hundred eleven million, three hundred forty-three thousand, four hundred one".