Base | Representation |
---|---|
bin | 1001100111010010110001… |
… | …00010000001010001101010 |
3 | 2202212002102112202101221221 |
4 | 10303221120202001101222 |
5 | 10232334402433002132 |
6 | 112544104041252254 |
7 | 4311260322622024 |
oct | 463513042012152 |
9 | 82762375671857 |
10 | 21141314344042 |
11 | 6810a87881212 |
12 | 24553b349408a |
13 | ba480452c419 |
14 | 5313606a9014 |
15 | 269e028e3e97 |
hex | 133a5888146a |
21141314344042 has 4 divisors (see below), whose sum is σ = 31711971516066. Its totient is φ = 10570657172020.
The previous prime is 21141314344037. The next prime is 21141314344043. The reversal of 21141314344042 is 24044341314112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 20533957536481 + 607356807561 = 4531441^2 + 779331^2 .
It is a junction number, because it is equal to n+sod(n) for n = 21141314343989 and 21141314344007.
It is not an unprimeable number, because it can be changed into a prime (21141314344043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5285328586009 + ... + 5285328586012.
Almost surely, 221141314344042 is an apocalyptic number.
21141314344042 is a deficient number, since it is larger than the sum of its proper divisors (10570657172024).
21141314344042 is a wasteful number, since it uses less digits than its factorization.
21141314344042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10570657172023.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 21141314344042 its reverse (24044341314112), we get a palindrome (45185655658154).
The spelling of 21141314344042 in words is "twenty-one trillion, one hundred forty-one billion, three hundred fourteen million, three hundred forty-four thousand, forty-two".
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