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211420123 = 891071492
BaseRepresentation
bin11001001101000…
…00001111011011
3112201211020212221
430212200033123
5413110420443
632551244511
75145020125
oct1446401733
9481736787
10211420123
11a9383082
125a979737
1334a55385
1420116215
1513862eed
hexc9a03db

211420123 has 12 divisors (see below), whose sum is σ = 217251720. Its totient is φ = 205701056.

The previous prime is 211420103. The next prime is 211420151. The reversal of 211420123 is 321024112.

211420123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a de Polignac number, because none of the positive numbers 2k-211420123 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211420097 and 211420106.

It is not an unprimeable number, because it can be changed into a prime (211420103) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1418853 + ... + 1419001.

It is an arithmetic number, because the mean of its divisors is an integer number (18104310).

Almost surely, 2211420123 is an apocalyptic number.

211420123 is a deficient number, since it is larger than the sum of its proper divisors (5831597).

211420123 is an equidigital number, since it uses as much as digits as its factorization.

211420123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 494 (or 345 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 211420123 is about 14540.2930850791. The cubic root of 211420123 is about 595.7290435017.

Adding to 211420123 its reverse (321024112), we get a palindrome (532444235).

The spelling of 211420123 in words is "two hundred eleven million, four hundred twenty thousand, one hundred twenty-three".

Divisors: 1 89 107 149 9523 13261 15943 22201 1418927 1975889 2375507 211420123