211421413001 has 4 divisors (see below), whose sum is σ = 211464293904. Its totient is φ = 211378532100.

The previous prime is 211421412997. The next prime is 211421413031. The reversal of 211421413001 is 100314124112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211421413001 - 2² = 211421412997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211421413031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21433055 + ... + 21442916.

It is an arithmetic number, because the mean of its divisors is an integer number (52866073476).

Almost surely, 2^211421413001 is an apocalyptic number.

It is an amenable number.

211421413001 is a deficient number, since it is larger than the sum of its proper divisors (42880903).

211421413001 is an equidigital number, since it uses as much as digits as its factorization.

211421413001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42880902.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 211421413001 its reverse (100314124112), we get a palindrome (311735537113).

The spelling of 211421413001 in words is "two hundred eleven billion, four hundred twenty-one million, four hundred thirteen thousand, one".