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21142204113 = 37047401371
BaseRepresentation
bin10011101100001011…
…000110111011010001
32000120102210020201210
4103230023012323101
5321244401012423
613413530450333
71345631525022
oct235413067321
960512706653
1021142204113
118a6a24a968
1241205939a9
131cbc214464
141047c8cc49
1583b18bb93
hex4ec2c6ed1

21142204113 has 4 divisors (see below), whose sum is σ = 28189605488. Its totient is φ = 14094802740.

The previous prime is 21142204103. The next prime is 21142204117. The reversal of 21142204113 is 31140224112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21142204113 - 221 = 21140106961 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21142204113.

It is not an unprimeable number, because it can be changed into a prime (21142204117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3523700683 + ... + 3523700688.

It is an arithmetic number, because the mean of its divisors is an integer number (7047401372).

Almost surely, 221142204113 is an apocalyptic number.

It is an amenable number.

21142204113 is a deficient number, since it is larger than the sum of its proper divisors (7047401375).

21142204113 is an equidigital number, since it uses as much as digits as its factorization.

21142204113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7047401374.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 21142204113 its reverse (31140224112), we get a palindrome (52282428225).

The spelling of 21142204113 in words is "twenty-one billion, one hundred forty-two million, two hundred four thousand, one hundred thirteen".

Divisors: 1 3 7047401371 21142204113