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2114221200001 = 3168200683871
BaseRepresentation
bin11110110001000001011…
…001110101001010000001
321111010011201012000010221
4132301001121311022001
5234114411111400001
64255132041423041
7305514241454041
oct36610131651201
97433151160127
102114221200001
117456aa827a39
122a190049aa81
131244a7450651
1474486527721
1539ee09911a1
hex1ec41675281

2114221200001 has 4 divisors (see below), whose sum is σ = 2182421883904. Its totient is φ = 2046020516100.

The previous prime is 2114221199999. The next prime is 2114221200029. The reversal of 2114221200001 is 1000021224112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2114221200001 - 21 = 2114221199999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2114221200041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34100341905 + ... + 34100341966.

It is an arithmetic number, because the mean of its divisors is an integer number (545605470976).

Almost surely, 22114221200001 is an apocalyptic number.

It is an amenable number.

2114221200001 is a deficient number, since it is larger than the sum of its proper divisors (68200683903).

2114221200001 is an equidigital number, since it uses as much as digits as its factorization.

2114221200001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68200683902.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 2114221200001 its reverse (1000021224112), we get a palindrome (3114242424113).

The spelling of 2114221200001 in words is "two trillion, one hundred fourteen billion, two hundred twenty-one million, two hundred thousand, one".

Divisors: 1 31 68200683871 2114221200001