Base | Representation |
---|---|
bin | 11110110001000011011… |
… | …100110101101101011011 |
3 | 21111010021002210211001201 |
4 | 132301003130311231123 |
5 | 234114443404340011 |
6 | 4255135305455031 |
7 | 305515136411554 |
oct | 36610334655533 |
9 | 7433232724051 |
10 | 2114255543131 |
11 | 745718154496 |
12 | 2a190baa1477 |
13 | 1244b15b6424 |
14 | 7448ad0732b |
15 | 39ee39c6cc1 |
hex | 1ec43735b5b |
2114255543131 has 4 divisors (see below), whose sum is σ = 2114324909392. Its totient is φ = 2114186176872.
The previous prime is 2114255543119. The next prime is 2114255543137. The reversal of 2114255543131 is 1313455524112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2114255543131 - 27 = 2114255543003 is a prime.
It is a super-2 number, since 2×21142555431312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2114255543137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34637391 + ... + 34698376.
It is an arithmetic number, because the mean of its divisors is an integer number (528581227348).
Almost surely, 22114255543131 is an apocalyptic number.
2114255543131 is a deficient number, since it is larger than the sum of its proper divisors (69366261).
2114255543131 is an equidigital number, since it uses as much as digits as its factorization.
2114255543131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69366260.
The product of its digits is 72000, while the sum is 37.
The spelling of 2114255543131 in words is "two trillion, one hundred fourteen billion, two hundred fifty-five million, five hundred forty-three thousand, one hundred thirty-one".
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