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211431414331 is a prime number
BaseRepresentation
bin1100010011101001001…
…0110101101000111011
3202012202000111200221101
43010322102311220323
511431002420224311
6241044044552231
721163316240404
oct3047222655073
9665660450841
10211431414331
1181738580a65
1234b87b52677
1316c26736a77
14a33a3b29ab
155776d2eec1
hex313a4b5a3b

211431414331 has 2 divisors, whose sum is σ = 211431414332. Its totient is φ = 211431414330.

The previous prime is 211431414269. The next prime is 211431414349. The reversal of 211431414331 is 133414134112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211431414331 is a prime.

It is a super-2 number, since 2×2114314143312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211431414331.

It is not a weakly prime, because it can be changed into another prime (211431414371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105715707165 + 105715707166.

It is an arithmetic number, because the mean of its divisors is an integer number (105715707166).

Almost surely, 2211431414331 is an apocalyptic number.

211431414331 is a deficient number, since it is larger than the sum of its proper divisors (1).

211431414331 is an equidigital number, since it uses as much as digits as its factorization.

211431414331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456, while the sum is 28.

Adding to 211431414331 its reverse (133414134112), we get a palindrome (344845548443).

The spelling of 211431414331 in words is "two hundred eleven billion, four hundred thirty-one million, four hundred fourteen thousand, three hundred thirty-one".