Base | Representation |
---|---|
bin | 1100010011101001001… |
… | …0110101101000111011 |
3 | 202012202000111200221101 |
4 | 3010322102311220323 |
5 | 11431002420224311 |
6 | 241044044552231 |
7 | 21163316240404 |
oct | 3047222655073 |
9 | 665660450841 |
10 | 211431414331 |
11 | 81738580a65 |
12 | 34b87b52677 |
13 | 16c26736a77 |
14 | a33a3b29ab |
15 | 5776d2eec1 |
hex | 313a4b5a3b |
211431414331 has 2 divisors, whose sum is σ = 211431414332. Its totient is φ = 211431414330.
The previous prime is 211431414269. The next prime is 211431414349. The reversal of 211431414331 is 133414134112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211431414331 is a prime.
It is a super-2 number, since 2×2114314143312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211431414331.
It is not a weakly prime, because it can be changed into another prime (211431414371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105715707165 + 105715707166.
It is an arithmetic number, because the mean of its divisors is an integer number (105715707166).
Almost surely, 2211431414331 is an apocalyptic number.
211431414331 is a deficient number, since it is larger than the sum of its proper divisors (1).
211431414331 is an equidigital number, since it uses as much as digits as its factorization.
211431414331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3456, while the sum is 28.
Adding to 211431414331 its reverse (133414134112), we get a palindrome (344845548443).
The spelling of 211431414331 in words is "two hundred eleven billion, four hundred thirty-one million, four hundred fourteen thousand, three hundred thirty-one".
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