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211433024113 is a prime number
BaseRepresentation
bin1100010011101001100…
…0111110101001110001
3202012202010112111010221
43010322120332221301
511431003323232423
6241044143253041
721163336023553
oct3047230765161
9665663474127
10211433024113
1181739480463
1234b885aa181
1316c26b7b6bc
14a33a6b14d3
15577704be5d
hex313a63ea71

211433024113 has 2 divisors, whose sum is σ = 211433024114. Its totient is φ = 211433024112.

The previous prime is 211433024093. The next prime is 211433024177. The reversal of 211433024113 is 311420334112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 200468421169 + 10964602944 = 447737^2 + 104712^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211433024113 is a prime.

It is not a weakly prime, because it can be changed into another prime (211433024213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105716512056 + 105716512057.

It is an arithmetic number, because the mean of its divisors is an integer number (105716512057).

Almost surely, 2211433024113 is an apocalyptic number.

It is an amenable number.

211433024113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211433024113 is an equidigital number, since it uses as much as digits as its factorization.

211433024113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 211433024113 its reverse (311420334112), we get a palindrome (522853358225).

The spelling of 211433024113 in words is "two hundred eleven billion, four hundred thirty-three million, twenty-four thousand, one hundred thirteen".