Base | Representation |
---|---|
bin | 1100010011101001100… |
… | …0111110101001110001 |
3 | 202012202010112111010221 |
4 | 3010322120332221301 |
5 | 11431003323232423 |
6 | 241044143253041 |
7 | 21163336023553 |
oct | 3047230765161 |
9 | 665663474127 |
10 | 211433024113 |
11 | 81739480463 |
12 | 34b885aa181 |
13 | 16c26b7b6bc |
14 | a33a6b14d3 |
15 | 577704be5d |
hex | 313a63ea71 |
211433024113 has 2 divisors, whose sum is σ = 211433024114. Its totient is φ = 211433024112.
The previous prime is 211433024093. The next prime is 211433024177. The reversal of 211433024113 is 311420334112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 200468421169 + 10964602944 = 447737^2 + 104712^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211433024113 is a prime.
It is not a weakly prime, because it can be changed into another prime (211433024213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105716512056 + 105716512057.
It is an arithmetic number, because the mean of its divisors is an integer number (105716512057).
Almost surely, 2211433024113 is an apocalyptic number.
It is an amenable number.
211433024113 is a deficient number, since it is larger than the sum of its proper divisors (1).
211433024113 is an equidigital number, since it uses as much as digits as its factorization.
211433024113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 211433024113 its reverse (311420334112), we get a palindrome (522853358225).
The spelling of 211433024113 in words is "two hundred eleven billion, four hundred thirty-three million, twenty-four thousand, one hundred thirteen".
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