2114332000131 has 16 divisors (see below), whose sum is σ = 3042549528480. Its totient is φ = 1298304971520.

The previous prime is 2114332000129. The next prime is 2114332000169. The reversal of 2114332000131 is 1310002334112.

It is not a de Polignac number, because 2114332000131 - 2¹ = 2114332000129 is a prime.

It is a super-2 number, since 2×2114332000131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2114332000098 and 2114332000107.

It is not an unprimeable number, because it can be changed into a prime (2114332000111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 58782066 + ... + 58818023.

It is an arithmetic number, because the mean of its divisors is an integer number (190159345530).

Almost surely, 2^{2114332000131} is an apocalyptic number.

2114332000131 is a deficient number, since it is larger than the sum of its proper divisors (928217528349).

2114332000131 is a wasteful number, since it uses less digits than its factorization.

2114332000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117600566.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2114332000131 its reverse (1310002334112), we get a palindrome (3424334334243).

The spelling of 2114332000131 in words is "two trillion, one hundred fourteen billion, three hundred thirty-two million, one hundred thirty-one", and thus it is an aban number.