Base | Representation |
---|---|
bin | 1100010011101001101… |
… | …0011101101001111001 |
3 | 202012202011021020221002 |
4 | 3010322122131221321 |
5 | 11431003423210431 |
6 | 241044155454345 |
7 | 21163342234211 |
oct | 3047232355171 |
9 | 665664236832 |
10 | 211433413241 |
11 | 81739716856 |
12 | 34b887573b5 |
13 | 16c26c8685b |
14 | a33a773241 |
15 | 57770c73cb |
hex | 313a69da79 |
211433413241 has 2 divisors, whose sum is σ = 211433413242. Its totient is φ = 211433413240.
The previous prime is 211433413189. The next prime is 211433413253. The reversal of 211433413241 is 142314334112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 184895700025 + 26537713216 = 429995^2 + 162904^2 .
It is a cyclic number.
It is not a de Polignac number, because 211433413241 - 222 = 211429218937 is a prime.
It is a super-3 number, since 3×2114334132413 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (211433413141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105716706620 + 105716706621.
It is an arithmetic number, because the mean of its divisors is an integer number (105716706621).
Almost surely, 2211433413241 is an apocalyptic number.
It is an amenable number.
211433413241 is a deficient number, since it is larger than the sum of its proper divisors (1).
211433413241 is an equidigital number, since it uses as much as digits as its factorization.
211433413241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 29.
Adding to 211433413241 its reverse (142314334112), we get a palindrome (353747747353).
The spelling of 211433413241 in words is "two hundred eleven billion, four hundred thirty-three million, four hundred thirteen thousand, two hundred forty-one".
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