Base | Representation |
---|---|
bin | 11110110001001000011… |
… | …111100011110101000011 |
3 | 21111010110222222220110002 |
4 | 132301020133203311003 |
5 | 234120132034024103 |
6 | 4255151531030215 |
7 | 305520214451636 |
oct | 36611037436503 |
9 | 7433428886402 |
10 | 2114340142403 |
11 | 745760987145 |
12 | 2a193429b36b |
13 | 1244c5c97078 |
14 | 74498249c1d |
15 | 39eeb138488 |
hex | 1ec487e3d43 |
2114340142403 has 4 divisors (see below), whose sum is σ = 2114597714280. Its totient is φ = 2114082570528.
The previous prime is 2114340142249. The next prime is 2114340142433. The reversal of 2114340142403 is 3042410434112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2114340142403 - 240 = 1014828514627 is a prime.
It is a super-2 number, since 2×21143401424032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2114340142433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128773625 + ... + 128790042.
It is an arithmetic number, because the mean of its divisors is an integer number (528649428570).
Almost surely, 22114340142403 is an apocalyptic number.
2114340142403 is a deficient number, since it is larger than the sum of its proper divisors (257571877).
2114340142403 is an equidigital number, since it uses as much as digits as its factorization.
2114340142403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 257571876.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 2114340142403 its reverse (3042410434112), we get a palindrome (5156750576515).
The spelling of 2114340142403 in words is "two trillion, one hundred fourteen billion, three hundred forty million, one hundred forty-two thousand, four hundred three".
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