Base | Representation |
---|---|
bin | 1001100111011000010110… |
… | …10110011000000101011001 |
3 | 2202212101011121220201102220 |
4 | 10303230023112120011121 |
5 | 10232412023442212101 |
6 | 112545321451214253 |
7 | 4311424552033644 |
oct | 463541326300531 |
9 | 82771147821386 |
10 | 21144314413401 |
11 | 6812287289783 |
12 | 2455ab0147389 |
13 | ba4b91c393aa |
14 | 531566ccca5b |
15 | 26a02ae9d636 |
hex | 133b0b598159 |
21144314413401 has 4 divisors (see below), whose sum is σ = 28192419217872. Its totient is φ = 14096209608932.
The previous prime is 21144314413381. The next prime is 21144314413489. The reversal of 21144314413401 is 10431441344112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21144314413401 - 242 = 16746267902297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (21144314413801) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3524052402231 + ... + 3524052402236.
It is an arithmetic number, because the mean of its divisors is an integer number (7048104804468).
Almost surely, 221144314413401 is an apocalyptic number.
It is an amenable number.
21144314413401 is a deficient number, since it is larger than the sum of its proper divisors (7048104804471).
21144314413401 is an equidigital number, since it uses as much as digits as its factorization.
21144314413401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7048104804470.
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 21144314413401 its reverse (10431441344112), we get a palindrome (31575755757513).
The spelling of 21144314413401 in words is "twenty-one trillion, one hundred forty-four billion, three hundred fourteen million, four hundred thirteen thousand, four hundred one".
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