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2114454011433 = 32618326918917
BaseRepresentation
bin11110110001001111010…
…001111011111000101001
321111010202221021001101120
4132301033101323320221
5234120400211331213
64255211115405453
7305523066356421
oct36611721737051
97433687231346
102114454011433
1174580a190685
122a1966453889
131245137554aa
14744a940b481
153a00612c423
hex1ec4f47be29

2114454011433 has 8 divisors (see below), whose sum is σ = 2819379795648. Its totient is φ = 1409582117424.

The previous prime is 2114454011399. The next prime is 2114454011443. The reversal of 2114454011433 is 3341104544112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2114454011433 - 225 = 2114420457001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2114454011394 and 2114454011403.

It is not an unprimeable number, because it can be changed into a prime (2114454011443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13380910 + ... + 13538007.

It is an arithmetic number, because the mean of its divisors is an integer number (352422474456).

Almost surely, 22114454011433 is an apocalyptic number.

It is an amenable number.

2114454011433 is a deficient number, since it is larger than the sum of its proper divisors (704925784215).

2114454011433 is a wasteful number, since it uses less digits than its factorization.

2114454011433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26945103.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 2114454011433 its reverse (3341104544112), we get a palindrome (5455558555545).

The spelling of 2114454011433 in words is "two trillion, one hundred fourteen billion, four hundred fifty-four million, eleven thousand, four hundred thirty-three".

Divisors: 1 3 26183 78549 26918917 80756751 704818003811 2114454011433