Base | Representation |
---|---|
bin | 11110110001001111010… |
… | …001111011111000101001 |
3 | 21111010202221021001101120 |
4 | 132301033101323320221 |
5 | 234120400211331213 |
6 | 4255211115405453 |
7 | 305523066356421 |
oct | 36611721737051 |
9 | 7433687231346 |
10 | 2114454011433 |
11 | 74580a190685 |
12 | 2a1966453889 |
13 | 1245137554aa |
14 | 744a940b481 |
15 | 3a00612c423 |
hex | 1ec4f47be29 |
2114454011433 has 8 divisors (see below), whose sum is σ = 2819379795648. Its totient is φ = 1409582117424.
The previous prime is 2114454011399. The next prime is 2114454011443. The reversal of 2114454011433 is 3341104544112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2114454011433 - 225 = 2114420457001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2114454011394 and 2114454011403.
It is not an unprimeable number, because it can be changed into a prime (2114454011443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13380910 + ... + 13538007.
It is an arithmetic number, because the mean of its divisors is an integer number (352422474456).
Almost surely, 22114454011433 is an apocalyptic number.
It is an amenable number.
2114454011433 is a deficient number, since it is larger than the sum of its proper divisors (704925784215).
2114454011433 is a wasteful number, since it uses less digits than its factorization.
2114454011433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26945103.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 2114454011433 its reverse (3341104544112), we get a palindrome (5455558555545).
The spelling of 2114454011433 in words is "two trillion, one hundred fourteen billion, four hundred fifty-four million, eleven thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •