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211455115340146 = 2105727557670073
BaseRepresentation
bin110000000101000100111011…
…000010010010100101110010
31000201200220121120002110222221
4300011010323002102211302
5210203440034011341041
62025421050002151254
762353061611205056
oct6005047302224562
91021626546073887
10211455115340146
1161415679a93447
121b87150235252a
1390cb1937a4772
143a306a71b5c66
15196a675b232d1
hexc0513b092972

211455115340146 has 4 divisors (see below), whose sum is σ = 317182673010222. Its totient is φ = 105727557670072.

The previous prime is 211455115340111. The next prime is 211455115340237. The reversal of 211455115340146 is 641043511554112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 161967900208921 + 49487215131225 = 12726661^2 + 7034715^2 .

It is a super-3 number, since 3×2114551153401463 (a number of 44 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52863778835035 + ... + 52863778835038.

Almost surely, 2211455115340146 is an apocalyptic number.

211455115340146 is a deficient number, since it is larger than the sum of its proper divisors (105727557670076).

211455115340146 is a wasteful number, since it uses less digits than its factorization.

211455115340146 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105727557670075.

The product of its (nonzero) digits is 288000, while the sum is 43.

Adding to 211455115340146 its reverse (641043511554112), we get a palindrome (852498626894258).

The spelling of 211455115340146 in words is "two hundred eleven trillion, four hundred fifty-five billion, one hundred fifteen million, three hundred forty thousand, one hundred forty-six".

Divisors: 1 2 105727557670073 211455115340146