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2115114412051 = 4349188707257
BaseRepresentation
bin11110110001110110101…
…001001010100000010011
321111012110221220212201201
4132301312221022200103
5234123223242141201
64255400430212031
7305545335601564
oct36616651124023
97435427825651
102115114412051
11746018a43413
122a1b0b654017
131245ba50b4a4
147452cdd816b
153a0440cb801
hex1ec76a4a813

2115114412051 has 4 divisors (see below), whose sum is σ = 2164303119352. Its totient is φ = 2065925704752.

The previous prime is 2115114412039. The next prime is 2115114412069. The reversal of 2115114412051 is 1502144115112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2115114412051 - 221 = 2115112314899 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2115114412751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24594353586 + ... + 24594353671.

It is an arithmetic number, because the mean of its divisors is an integer number (541075779838).

Almost surely, 22115114412051 is an apocalyptic number.

2115114412051 is a deficient number, since it is larger than the sum of its proper divisors (49188707301).

2115114412051 is an equidigital number, since it uses as much as digits as its factorization.

2115114412051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49188707300.

The product of its (nonzero) digits is 1600, while the sum is 28.

Adding to 2115114412051 its reverse (1502144115112), we get a palindrome (3617258527163).

The spelling of 2115114412051 in words is "two trillion, one hundred fifteen billion, one hundred fourteen million, four hundred twelve thousand, fifty-one".

Divisors: 1 43 49188707257 2115114412051